what is the magnitude of the force exrted on the side and circular base of the tank

Mass cancels because friction is assumed proportional to the normal force, which in turn is proportional to mass. Note that mass cancels, implying that, in this example, it does not matter how heavily loaded the car is to negotiate the turn. A higher coefficient would also allow the car to negotiate the curve at a higher speed, but if the coefficient of friction is less, the safe speed would be less than 25 m/s. The car still negotiates the curve if the coefficient is greater than 0.13, because static friction is a responsive force, able to assume a value less than but no more than μ s N. SignificanceThe coefficient of friction found in Figure 6.21(b) is much smaller than is typically found between tires and roads. (Because coefficients of friction are approximate, the answer is given to only two digits.) Thus, the magnitude of centripetal force F c F c is For uniform circular motion, the acceleration is the centripetal acceleration. According to Newton’s second law of motion, net force is mass times acceleration: F net = m a.

The direction of a centripetal force is toward the center of curvature, the same as the direction of centripetal acceleration. Any net force causing uniform circular motion is called a centripetal force. Just a few examples are the tension in the rope on a tether ball, the force of Earth’s gravity on the Moon, friction between roller skates and a rink floor, a banked roadway’s force on a car, and forces on the tube of a spinning centrifuge.

Any force or combination of forces can cause a centripetal or radial acceleration. This acceleration acts along the radius of the curved path and is thus also referred to as a radial acceleration.Īn acceleration must be produced by a force. Angular velocity gives the rate at which the object is turning through the curve, in units of rad/s.

What is the magnitude of the force exrted on the side and circular base of the tank